2(x^2+3x)=5

Solution for 2(x^2+3x)=5 equation:

2(x^2+3x)=5

We move all terms to the left:

2(x^2+3x)-(5)=0

We multiply parentheses

2x^2+6x-5=0

a = 2; b = 6; c = -5;
Δ = b2-4ac
Δ = 62-4·2·(-5)
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{19}}{2*2}=\frac{-6-2\sqrt{19}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{19}}{2*2}=\frac{-6+2\sqrt{19}}{4}
$